4473: Arpa’s abnormal DNA and Mehrdad’s deep interest

内存限制:256 MB 时间限制:2 S 标准输入输出
题目类型:传统 评测方式:文本比较 上传者:
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题目描述

time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

All of us know that girls in Arpa’s land are... ok, you’ve got the idea :D

Anyone knows that Arpa isn't a normal man, he is ... well, sorry, I can't explain it more. Mehrdad is interested about the reason, so he asked Sipa, one of the best biology scientists in Arpa's land, for help. Sipa has a DNA editor.

Sipa put Arpa under the DNA editor. DNA editor showed Arpa's DNA as a string S consisting of n lowercase English letters. Also Sipa has another DNA T consisting of lowercase English letters that belongs to a normal man.

Now there are (n+1) options to change Arpa's DNA, numbered from 0 to n. i-th of them is to put T between i-th and (i+1)-th characters of S (0≤in). If i=0, T will be put before S, and if i=n, it will be put after S.

Mehrdad wants to choose the most interesting option for Arpa's DNA among these n+1 options. DNA A is more interesting than B if A is lexicographically smaller than B. Mehrdad asked Sipa q questions:

Given integers l,r,k,x,y, what is the most interesting option if we only consider such options i that lir and ? If there are several most interesting options, Mehrdad wants to know one with the smallest number i.

Since Sipa is a biology scientist but not a programmer, you should help him.

Input

The first line contains strings S, T and integer q (1≤|S|,|T|,q≤105)− Arpa's DNA, the DNA of a normal man, and the number of Mehrdad's questions. The strings S and T consist only of small English letters.

Next q lines describe the Mehrdad's questions. Each of these lines contain five integers l,r,k,x,y (0≤lrn, 1≤kn, 0≤xy<k).

Output

Print q integers. The j-th of them should be the number i of the most interesting option among those that satisfy the conditions of the j-th question. If there is no option i satisfying the conditions in some question, print -1.

Examples
Input
abc d 4
0 3 2 0 0
0 3 1 0 0
1 2 1 0 0
0 1 3 2 2
Output
2 3 2 -1 
Input
abbbbbbaaa baababaaab 10
1 2 1 0 0
2 7 8 4 7
2 3 9 2 8
3 4 6 1 1
0 8 5 2 4
2 8 10 4 7
7 10 1 0 0
1 4 6 0 2
0 9 8 0 6
4 8 5 0 1
Output
1 4 2 -1 2 4 10 1 1 5 
Note

Explanation of first sample case:

In the first question Sipa has two options: dabc (i=0) and abdc (i=2). The latter (abcd) is better than abdc, so answer is 2.

In the last question there is no i such that 0≤i≤1 and .