5279: Om Nom and Necklace

内存限制:256 MB 时间限制:2 S
题面:传统 评测方式:文本比较 上传者:
提交:0 通过:0

题目描述

D. Om Nom and Necklace
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
One day Om Nom found a thread with n beads of different colors. He decided to cut the first several beads from this thread to make a bead necklace and present it to his girlfriend Om Nelly.
Om Nom knows that his girlfriend loves beautiful patterns. That's why he wants the beads on the necklace to form a regular pattern. A sequence of beads S is regular if it can be represented as S=A+B+A+B+A+...+A+B+A, where A and B are some bead sequences, "+" is the concatenation of sequences, there are exactly 2k+1 summands in this sum, among which there are k+1 "A" summands and k "B" summands that follow in alternating order. Om Nelly knows that her friend is an eager mathematician, so she doesn't mind if A or B is an empty sequence.
Help Om Nom determine in which ways he can cut off the first several beads from the found thread (at least one; probably, all) so that they form a regular pattern. When Om Nom cuts off the beads, he doesn't change their order.
Input
The first line contains two integers n, k (1≤n,k≤1000000) − the number of beads on the thread that Om Nom found and number k from the definition of the regular sequence above.
The second line contains the sequence of n lowercase Latin letters that represent the colors of the beads. Each color corresponds to a single letter.
Output
Print a string consisting of n zeroes and ones. Position i (1≤in) must contain either number one if the first i beads on the thread form a regular sequence, or a zero otherwise.
Examples
Input
7 2
bcabcab
Output
0000011
Input
21 2
ababaababaababaababaa
Output
000110000111111000011
Note
In the first sample test a regular sequence is both a sequence of the first 6 beads (we can take A="", B="bca"), and a sequence of the first 7 beads (we can take A="b", B="ca").
In the second sample test, for example, a sequence of the first 13 beads is regular, if we take A="aba", B="ba".

输入样例 复制


输出样例 复制